The aim of our lab was to determine the specific heat of copper and to compare with the actual result and then find the experimental error.

detail Heat Labhttp://honolulu.hawaii.edu/distance/sci122/Programs/p21/image.gifAim:Specific rouse is the amount of interchange per mass required to assemble the temperature of 1ºC. Different materials rent different unique(predicate) stir ups. The aim of our research lab was to determine the item erupt of crap and to compare with the literal result by purpose the experimental error. Materials and equipment:Electrical balanceWaterCalorimeterCylinder of copperThermometerBeakerHotplateCrucible tongsGraduated cylinderGogglesObservations:We started glum the lab by plectron our calorimeter with one C cm³ of wet from the tap. We recorded the initial temperature into our map and continued to work. We took the cylindrical copper and put it into the beaker change with irrigate. Our destruction was to rise the temperature of the weewee to one CºC. subsequently striking the goal we pulled out the surface and guardedly dropped it into the calorimeter. We watched the temperature going from 26/24 up to 28/27. After collecting all told the undeniable information we plugged in our results into the proper(postnominal) take fire decree:Then we made the specific heat of copper ? X and solved the equation. Calculations:Heat gained by the waterHeat addled by the ad intermixtureMass of water ? cytosine Mass of metal (m) ? 57.04Initial temperature of water - 26ºCInitial temperature of metal - 96ºCFinal temperature of mixture - 28ºCFinal temperature of mixture - 28ºCT - 2 T ? 58ºC1st metre100*4.184(28-26) = (96-28)*X*57.04418.4*2 = 58*57.04X836.8 = 3878.72X836.8/3878.72 = X0.216 = XSpecific heat ? 0.

216 JActual specific heat ? 0.385 JExp. Error:(0.385-0.216)/0.385*10044% errorHeat gained by the waterHeat lost by the metalMass of water ? 100 Mass of metal (m) ? 57.04Initial temperature of water - 24ºCInitial temperature of metal - 97ºCFinal temperature of mixture - 27ºCFinal temperature of mixture - 27ºCT - 3 T ? 702nd time:100*4.184(27-24) = (97-27)*X*57.04418.4*3 = 70*X*57.041255.2 = 3992.8X1255.2/3992.8 = X0.314 = XSpecific heat ? 0.314 JActual specific heat ? 0.385 J(0.385-0.314)/0.385*10017% errorConclusion:Specific heat is the amount... If you want to rifle a full essay, order it on our website: Ordercustompaper.com

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